Time constant
τ = RC
The product of resistance and capacitance sets the first-order time scale.
Calculate an ideal first-order RC charging or discharging transient at a selected time.
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For discharge mode, the engine targets 0 V. The source-voltage field is therefore ignored by the transient equation.
The time constant is τ = RC. After one time constant a charging capacitor has traversed about 63.2% of the difference to its final value; after about five time constants it is effectively settled for many engineering purposes.
ESR, leakage, dielectric absorption, source resistance, current limiting, tolerance, temperature, and nonlinear components are not modeled here.
Use the RC Time Constant Calculator to calculate τ = RC and the ideal charging or discharging capacitor voltage, current, charge, and stored energy at a selected time.
τ = RC
The product of resistance and capacitance sets the first-order time scale.
V_C(t) = V_s + (V_0−V_s)e^(−t/RC)
The capacitor voltage exponentially approaches the source voltage.
V_C(t) = V_0e^(−t/RC)
With a zero-volt target, the stored voltage decays exponentially.
Set R = 1,000 Ω, C = 100 µF, source = 5 V, initial voltage = 0 V, and time = 100 ms.
Result: The example demonstrates the 63.2% one-time-constant charging rule.
A first-order RC network changes exponentially toward its final value. One time constant corresponds to 63.2% of the total charging transition, or 36.8% of the initial voltage remaining during ideal discharge.
The model treats R and C as ideal lumped components. Source impedance, capacitor ESR and leakage, dielectric absorption, component tolerance, temperature, current limiting, and nonlinear connected circuitry can alter the actual waveform.
After 5τ, an ideal first-order charging response has completed about 99.3% of its transition.
No in the ideal model. A capacitor's voltage is continuous unless an impulse current is allowed.
Yes. Any meaningful source resistance in series with the capacitor should be included in the effective R used for the time constant.
Case: Evaluate a 0 V to Vs charge at t = RC.
Expected: Capacitor voltage should be approximately 0.632 Vs.
Case: Evaluate the same charge at t = 5RC.
Expected: Capacitor voltage should be approximately 0.993 Vs.
Shared with the Introductory Circuits Workbench, which also covers the transient response of RL and RLC networks.
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